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1164070041317 is a prime number
BaseRepresentation
bin10000111100000111111…
…110110011011011100101
311010021200001011002112222
4100330013332303123211
5123033003412310232
62250433312522125
7150046512043631
oct20740776633345
94107601132488
101164070041317
11409752211367
12169730850345
1385a0480b421
14404ac703dc1
15204306b1d12
hex10f07fb36e5

1164070041317 has 2 divisors, whose sum is σ = 1164070041318. Its totient is φ = 1164070041316.

The previous prime is 1164070041247. The next prime is 1164070041319. The reversal of 1164070041317 is 7131400704611.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1079938718401 + 84131322916 = 1039201^2 + 290054^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1164070041317 is a prime.

It is a super-2 number, since 2×11640700413172 (a number of 25 digits) contains 22 as substring.

Together with 1164070041319, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1164070041319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 582035020658 + 582035020659.

It is an arithmetic number, because the mean of its divisors is an integer number (582035020659).

Almost surely, 21164070041317 is an apocalyptic number.

It is an amenable number.

1164070041317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1164070041317 is an equidigital number, since it uses as much as digits as its factorization.

1164070041317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14112, while the sum is 35.

Adding to 1164070041317 its reverse (7131400704611), we get a palindrome (8295470745928).

The spelling of 1164070041317 in words is "one trillion, one hundred sixty-four billion, seventy million, forty-one thousand, three hundred seventeen".