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116961300235 = 5132207815317
BaseRepresentation
bin110110011101101101…
…1111100111100001011
3102011220020022200001201
41230323123330330023
53404014043101420
6125421542325031
711310260435263
oct1547333747413
9364806280051
10116961300235
114566a671aaa
121a802129777
13b04c7a3080
1459379487a3
15309831a10a
hex1b3b6fcf0b

116961300235 has 16 divisors (see below), whose sum is σ = 151218660096. Its totient is φ = 86332180608.

The previous prime is 116961300227. The next prime is 116961300263. The reversal of 116961300235 is 532003169611.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 116961300235 - 23 = 116961300227 is a prime.

It is a super-2 number, since 2×1169613002352 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 116961300194 and 116961300203.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 264204 + ... + 551113.

It is an arithmetic number, because the mean of its divisors is an integer number (9451166256).

Almost surely, 2116961300235 is an apocalyptic number.

116961300235 is a deficient number, since it is larger than the sum of its proper divisors (34257359861).

116961300235 is a wasteful number, since it uses less digits than its factorization.

116961300235 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 817542.

The product of its (nonzero) digits is 29160, while the sum is 37.

Adding to 116961300235 its reverse (532003169611), we get a palindrome (648964469846).

The spelling of 116961300235 in words is "one hundred sixteen billion, nine hundred sixty-one million, three hundred thousand, two hundred thirty-five".

Divisors: 1 5 13 65 2207 11035 28691 143455 815317 4076585 10599121 52995605 1799404619 8997023095 23392260047 116961300235