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11696919673 is a prime number
BaseRepresentation
bin10101110010011000…
…01101010001111001
31010012011211002022011
422321030031101321
5142423402412143
65212401325521
7562601114425
oct127114152171
933164732264
1011696919673
114a6267396a
1223253368a1
13114542895a
147cd685b85
15486d53e9d
hex2b930d479

11696919673 has 2 divisors, whose sum is σ = 11696919674. Its totient is φ = 11696919672.

The previous prime is 11696919671. The next prime is 11696919679. The reversal of 11696919673 is 37691969611.

11696919673 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9109366249 + 2587553424 = 95443^2 + 50868^2 .

It is a cyclic number.

It is not a de Polignac number, because 11696919673 - 21 = 11696919671 is a prime.

It is a super-2 number, since 2×116969196732 (a number of 21 digits) contains 22 as substring.

Together with 11696919671, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11696919671) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5848459836 + 5848459837.

It is an arithmetic number, because the mean of its divisors is an integer number (5848459837).

Almost surely, 211696919673 is an apocalyptic number.

It is an amenable number.

11696919673 is a deficient number, since it is larger than the sum of its proper divisors (1).

11696919673 is an equidigital number, since it uses as much as digits as its factorization.

11696919673 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3306744, while the sum is 58.

The spelling of 11696919673 in words is "eleven billion, six hundred ninety-six million, nine hundred nineteen thousand, six hundred seventy-three".