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11700474211303 is a prime number
BaseRepresentation
bin1010101001000011101010…
…0110111110101111100111
31112102112222011110111122221
42222100322212332233213
53013200032344230203
640515042412533211
72315221441555153
oct252207246765747
945375864414587
1011700474211303
113801163730579
12138b769181207
1366b471bb6ba7
142c643d83c063
151545521d3abd
hexaa43a9bebe7

11700474211303 has 2 divisors, whose sum is σ = 11700474211304. Its totient is φ = 11700474211302.

The previous prime is 11700474211259. The next prime is 11700474211337. The reversal of 11700474211303 is 30311247400711.

It is an a-pointer prime, because the next prime (11700474211337) can be obtained adding 11700474211303 to its sum of digits (34).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11700474211303 - 213 = 11700474203111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11700474911303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5850237105651 + 5850237105652.

It is an arithmetic number, because the mean of its divisors is an integer number (5850237105652).

Almost surely, 211700474211303 is an apocalyptic number.

11700474211303 is a deficient number, since it is larger than the sum of its proper divisors (1).

11700474211303 is an equidigital number, since it uses as much as digits as its factorization.

11700474211303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14112, while the sum is 34.

The spelling of 11700474211303 in words is "eleven trillion, seven hundred billion, four hundred seventy-four million, two hundred eleven thousand, three hundred three".