Base | Representation |
---|---|
bin | 10001000010001010110… |
… | …100011010011011010111 |
3 | 11010220102100100020102211 |
4 | 101002022310122123113 |
5 | 123134301341200210 |
6 | 2253425313214251 |
7 | 150366366452653 |
oct | 21021264323327 |
9 | 4126370306384 |
10 | 1170560100055 |
11 | 411482729575 |
12 | 16aa42261387 |
13 | 864ca28b378 |
14 | 4092663ba63 |
15 | 206b034c38a |
hex | 1108ad1a6d7 |
1170560100055 has 4 divisors (see below), whose sum is σ = 1404672120072. Its totient is φ = 936448080040.
The previous prime is 1170560100029. The next prime is 1170560100067. The reversal of 1170560100055 is 5500010650711.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1170560100055 - 211 = 1170560098007 is a prime.
It is a super-2 number, since 2×11705601000552 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117056010001 + ... + 117056010010.
It is an arithmetic number, because the mean of its divisors is an integer number (351168030018).
Almost surely, 21170560100055 is an apocalyptic number.
1170560100055 is a deficient number, since it is larger than the sum of its proper divisors (234112020017).
1170560100055 is an equidigital number, since it uses as much as digits as its factorization.
1170560100055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 234112020016.
The product of its (nonzero) digits is 5250, while the sum is 31.
Adding to 1170560100055 its reverse (5500010650711), we get a palindrome (6670570750766).
The spelling of 1170560100055 in words is "one trillion, one hundred seventy billion, five hundred sixty million, one hundred thousand, fifty-five".
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