Base | Representation |
---|---|
bin | 110110100000100100… |
… | …0000000100000111101 |
3 | 102012010212220021100111 |
4 | 1231001020000200331 |
5 | 3404213011012133 |
6 | 125435232030021 |
7 | 11312526555511 |
oct | 1550110004075 |
9 | 365125807314 |
10 | 117056735293 |
11 | 45709525853 |
12 | 1a82a092311 |
13 | b0664a8b14 |
14 | 59464ac141 |
15 | 30a18bc1cd |
hex | 1b4120083d |
117056735293 has 2 divisors, whose sum is σ = 117056735294. Its totient is φ = 117056735292.
The previous prime is 117056735273. The next prime is 117056735297. The reversal of 117056735293 is 392537650711.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 77460909124 + 39595826169 = 278318^2 + 198987^2 .
It is a cyclic number.
It is not a de Polignac number, because 117056735293 - 213 = 117056727101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (117056735297) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58528367646 + 58528367647.
It is an arithmetic number, because the mean of its divisors is an integer number (58528367647).
Almost surely, 2117056735293 is an apocalyptic number.
It is an amenable number.
117056735293 is a deficient number, since it is larger than the sum of its proper divisors (1).
117056735293 is an equidigital number, since it uses as much as digits as its factorization.
117056735293 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1190700, while the sum is 49.
The spelling of 117056735293 in words is "one hundred seventeen billion, fifty-six million, seven hundred thirty-five thousand, two hundred ninety-three".
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