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11712103 = 13900931
BaseRepresentation
bin101100101011…
…011001100111
3211001000222121
4230223121213
510444241403
61055010411
7201360034
oct54533147
924030877
1011712103
11667a527
123b09a07
132570c50
1417ac38b
1510653bd
hexb2b667

11712103 has 4 divisors (see below), whose sum is σ = 12613048. Its totient is φ = 10811160.

The previous prime is 11712097. The next prime is 11712119. The reversal of 11712103 is 30121711.

11712103 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11712103 - 213 = 11703911 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11712163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 450453 + ... + 450478.

It is an arithmetic number, because the mean of its divisors is an integer number (3153262).

Almost surely, 211712103 is an apocalyptic number.

11712103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11712103 is a deficient number, since it is larger than the sum of its proper divisors (900945).

11712103 is an equidigital number, since it uses as much as digits as its factorization.

11712103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 900944.

The product of its (nonzero) digits is 42, while the sum is 16.

The square root of 11712103 is about 3422.2949902076. The cubic root of 11712103 is about 227.0971205575.

Adding to 11712103 its reverse (30121711), we get a palindrome (41833814).

The spelling of 11712103 in words is "eleven million, seven hundred twelve thousand, one hundred three".

Divisors: 1 13 900931 11712103