117125335342080 has 1408 divisors, whose sum is σ = 461228913331200. Its totient is φ = 27999707332608.

The previous prime is 117125335342039. The next prime is 117125335342087. The reversal of 117125335342080 is 80243533521711.

117125335342080 is a `hidden beast` number, since 1 + 1 + 7 + 1 + 2 + 5 + 33 + 534 + 2 + 0 + 80 = 666.

It is a super-3 number, since 3×117125335342080³ (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (117125335342087) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 45415018231 + ... + 45415020809.

Almost surely, 2^{117125335342080} is an apocalyptic number.

117125335342080 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 117125335342080, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (230614456665600).

117125335342080 is an abundant number, since it is smaller than the sum of its proper divisors (344103577989120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

117125335342080 is a wasteful number, since it uses less digits than its factorization.

117125335342080 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3346 (or 3322 counting only the distinct ones).

The product of its (nonzero) digits is 604800, while the sum is 45.

Adding to 117125335342080 its reverse (80243533521711), we get a palindrome (197368868863791).

The spelling of 117125335342080 in words is "one hundred seventeen trillion, one hundred twenty-five billion, three hundred thirty-five million, three hundred forty-two thousand, eighty".