Base | Representation |
---|---|
bin | 1010101001110100000011… |
… | …0100000110100000101111 |
3 | 1112110210111101120022122110 |
4 | 2222131000310012200233 |
5 | 3013403133040404200 |
6 | 40525031332215103 |
7 | 2316161352360060 |
oct | 252350064064057 |
9 | 45423441508573 |
10 | 11713463216175 |
11 | 3806719686146 |
12 | 139219316a493 |
13 | 66c761c090a6 |
14 | 2c6d12944567 |
15 | 154a626b2b50 |
hex | aa740d0682f |
11713463216175 has 24 divisors (see below), whose sum is σ = 22132867639936. Its totient is φ = 5354726041440.
The previous prime is 11713463216149. The next prime is 11713463216179. The reversal of 11713463216175 is 57161236431711.
It is not a de Polignac number, because 11713463216175 - 210 = 11713463215151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11713463216179) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 11155678729 + ... + 11155679778.
Almost surely, 211713463216175 is an apocalyptic number.
11713463216175 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11713463216175 is a deficient number, since it is larger than the sum of its proper divisors (10419404423761).
11713463216175 is a wasteful number, since it uses less digits than its factorization.
11713463216175 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22311358527 (or 22311358522 counting only the distinct ones).
The product of its digits is 635040, while the sum is 48.
Adding to 11713463216175 its reverse (57161236431711), we get a palindrome (68874699647886).
The spelling of 11713463216175 in words is "eleven trillion, seven hundred thirteen billion, four hundred sixty-three million, two hundred sixteen thousand, one hundred seventy-five".
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