Base | Representation |
---|---|
bin | 11010101000101111000011… |
… | …100000011101011100101110 |
3 | 120100210021210022001010122222 |
4 | 122220233003200131130232 |
5 | 110323330123321033000 |
6 | 1053053141155435342 |
7 | 33450462235146116 |
oct | 3250570340353456 |
9 | 510707708033588 |
10 | 117148513064750 |
11 | 3436645062a182 |
12 | 111801bbbb5b52 |
13 | 504a0990ac79b |
14 | 20d0038266046 |
15 | d8247d1c7a85 |
hex | 6a8bc381d72e |
117148513064750 has 64 divisors (see below), whose sum is σ = 225070187037696. Its totient is φ = 45642793588000.
The previous prime is 117148513064747. The next prime is 117148513064761. The reversal of 117148513064750 is 57460315841711.
It is a happy number.
It is a super-2 number, since 2×1171485130647502 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 117148513064692 and 117148513064701.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 38285282 + ... + 41231781.
It is an arithmetic number, because the mean of its divisors is an integer number (3516721672464).
Almost surely, 2117148513064750 is an apocalyptic number.
117148513064750 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
117148513064750 is a deficient number, since it is larger than the sum of its proper divisors (107921673972946).
117148513064750 is an equidigital number, since it uses as much as digits as its factorization.
117148513064750 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79517234 (or 79517224 counting only the distinct ones).
The product of its (nonzero) digits is 2822400, while the sum is 53.
The spelling of 117148513064750 in words is "one hundred seventeen trillion, one hundred forty-eight billion, five hundred thirteen million, sixty-four thousand, seven hundred fifty".
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