Base | Representation |
---|---|
bin | 1010101001111100011000… |
… | …0110110011111101000111 |
3 | 1112111000021020111211111022 |
4 | 2222133012012303331013 |
5 | 3013422223032200011 |
6 | 40530041255301355 |
7 | 2316300645366503 |
oct | 252370606637507 |
9 | 45430236454438 |
10 | 11715699490631 |
11 | 3807666a31254 |
12 | 13926b807a85b |
13 | 66ca2a2cb606 |
14 | 2c7085945303 |
15 | 154b43b978db |
hex | aa7c61b3f47 |
11715699490631 has 2 divisors, whose sum is σ = 11715699490632. Its totient is φ = 11715699490630.
The previous prime is 11715699490577. The next prime is 11715699490633. The reversal of 11715699490631 is 13609499651711.
It is a strong prime.
It is an emirp because it is prime and its reverse (13609499651711) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11715699490631 - 210 = 11715699489607 is a prime.
It is a super-2 number, since 2×117156994906312 (a number of 27 digits) contains 22 as substring.
Together with 11715699490633, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11715699490633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5857849745315 + 5857849745316.
It is an arithmetic number, because the mean of its divisors is an integer number (5857849745316).
Almost surely, 211715699490631 is an apocalyptic number.
11715699490631 is a deficient number, since it is larger than the sum of its proper divisors (1).
11715699490631 is an equidigital number, since it uses as much as digits as its factorization.
11715699490631 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11022480, while the sum is 62.
The spelling of 11715699490631 in words is "eleven trillion, seven hundred fifteen billion, six hundred ninety-nine million, four hundred ninety thousand, six hundred thirty-one".
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