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11723476589 = 111065770599
BaseRepresentation
bin10101110101100011…
…00000111001101101
31010021000210022112122
422322301200321231
5143002202222324
65215150442325
7563342623016
oct127261407155
933230708478
1011723476589
114a76662530
1223322033a5
13114aa966c6
147d2dda00d
1548934ca5e
hex2bac60e6d

11723476589 has 4 divisors (see below), whose sum is σ = 12789247200. Its totient is φ = 10657705980.

The previous prime is 11723476561. The next prime is 11723476591. The reversal of 11723476589 is 98567432711.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11723476589 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11723476589.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11723476189) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 532885289 + ... + 532885310.

It is an arithmetic number, because the mean of its divisors is an integer number (3197311800).

Almost surely, 211723476589 is an apocalyptic number.

It is an amenable number.

11723476589 is a deficient number, since it is larger than the sum of its proper divisors (1065770611).

11723476589 is a wasteful number, since it uses less digits than its factorization.

11723476589 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1065770610.

The product of its digits is 2540160, while the sum is 53.

The spelling of 11723476589 in words is "eleven billion, seven hundred twenty-three million, four hundred seventy-six thousand, five hundred eighty-nine".

Divisors: 1 11 1065770599 11723476589