Base | Representation |
---|---|
bin | 110110101010110011… |
… | …1100011000101101111 |
3 | 102020000211211202022011 |
4 | 1231111213203011233 |
5 | 3410414020011240 |
6 | 125533313102051 |
7 | 11324203122154 |
oct | 1552547430557 |
9 | 366024752264 |
10 | 117400547695 |
11 | 45875604132 |
12 | 1a905257927 |
13 | b0bc7a6802 |
14 | 597a00822b |
15 | 30c1b826ea |
hex | 1b559e316f |
117400547695 has 4 divisors (see below), whose sum is σ = 140880657240. Its totient is φ = 93920438152.
The previous prime is 117400547687. The next prime is 117400547701. The reversal of 117400547695 is 596745004711.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 596745004711 = 6691 ⋅89186221.
It is a cyclic number.
It is not a de Polignac number, because 117400547695 - 23 = 117400547687 is a prime.
It is a Smith number, since the sum of its digits (49) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11740054765 + ... + 11740054774.
It is an arithmetic number, because the mean of its divisors is an integer number (35220164310).
Almost surely, 2117400547695 is an apocalyptic number.
117400547695 is a deficient number, since it is larger than the sum of its proper divisors (23480109545).
117400547695 is an equidigital number, since it uses as much as digits as its factorization.
117400547695 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23480109544.
The product of its (nonzero) digits is 1058400, while the sum is 49.
The spelling of 117400547695 in words is "one hundred seventeen billion, four hundred million, five hundred forty-seven thousand, six hundred ninety-five".
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