Base | Representation |
---|---|
bin | 11010101110010101110000… |
… | …101111011110110110001110 |
3 | 120102011002221122200110100021 |
4 | 122232111300233132312032 |
5 | 110401132424404102400 |
6 | 1053550120122452354 |
7 | 33520345643231626 |
oct | 3256256057366616 |
9 | 512132848613307 |
10 | 117533671550350 |
11 | 344a48285480a0 |
12 | 112229909640ba |
13 | 50774ba982133 |
14 | 210493529b886 |
15 | d8c4c1b6571a |
hex | 6ae570bded8e |
117533671550350 has 24 divisors (see below), whose sum is σ = 238486504456008. Its totient is φ = 42739516927200.
The previous prime is 117533671550177. The next prime is 117533671550353. The reversal of 117533671550350 is 53055176335711.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (117533671550353) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 106848791769 + ... + 106848792868.
It is an arithmetic number, because the mean of its divisors is an integer number (9936937685667).
Almost surely, 2117533671550350 is an apocalyptic number.
117533671550350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
117533671550350 is an abundant number, since it is smaller than the sum of its proper divisors (120952832905658).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
117533671550350 is a wasteful number, since it uses less digits than its factorization.
117533671550350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 213697584660 (or 213697584655 counting only the distinct ones).
The product of its (nonzero) digits is 4961250, while the sum is 52.
The spelling of 117533671550350 in words is "one hundred seventeen trillion, five hundred thirty-three billion, six hundred seventy-one million, five hundred fifty thousand, three hundred fifty".
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