11797011347053 has 2 divisors, whose sum is σ = 11797011347054. Its totient is φ = 11797011347052.

The previous prime is 11797011347047. The next prime is 11797011347063. The reversal of 11797011347053 is 35074311079711.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11466336895204 + 330674451849 = 3386198^2 + 575043^2 .

It is a cyclic number.

It is not a de Polignac number, because 11797011347053 - 2¹⁷ = 11797011215981 is a prime.

It is a super-2 number, since 2×11797011347053² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11797011346988 and 11797011347006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11797011347063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5898505673526 + 5898505673527.

It is an arithmetic number, because the mean of its divisors is an integer number (5898505673527).

Almost surely, 2^{11797011347053} is an apocalyptic number.

It is an amenable number.

11797011347053 is a deficient number, since it is larger than the sum of its proper divisors (1).

11797011347053 is an equidigital number, since it uses as much as digits as its factorization.

11797011347053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 555660, while the sum is 49.

The spelling of 11797011347053 in words is "eleven trillion, seven hundred ninety-seven billion, eleven million, three hundred forty-seven thousand, fifty-three".