Base | Representation |
---|---|
bin | 10101111111111001… |
… | …10100101110011101 |
3 | 1010111002012210112022 |
4 | 22333330310232131 |
5 | 143141420434303 |
6 | 5231532145525 |
7 | 565446061361 |
oct | 127774645635 |
9 | 33432183468 |
10 | 11810327453 |
11 | 5010692901 |
12 | 23573082a5 |
13 | 1162a85152 |
14 | 8007672a1 |
15 | 491ca6438 |
hex | 2bff34b9d |
11810327453 has 2 divisors, whose sum is σ = 11810327454. Its totient is φ = 11810327452.
The previous prime is 11810327449. The next prime is 11810327467. The reversal of 11810327453 is 35472301811.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8302489924 + 3507837529 = 91118^2 + 59227^2 .
It is a cyclic number.
It is not a de Polignac number, because 11810327453 - 22 = 11810327449 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11810327423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5905163726 + 5905163727.
It is an arithmetic number, because the mean of its divisors is an integer number (5905163727).
Almost surely, 211810327453 is an apocalyptic number.
It is an amenable number.
11810327453 is a deficient number, since it is larger than the sum of its proper divisors (1).
11810327453 is an equidigital number, since it uses as much as digits as its factorization.
11810327453 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 35.
The spelling of 11810327453 in words is "eleven billion, eight hundred ten million, three hundred twenty-seven thousand, four hundred fifty-three".
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