Base | Representation |
---|---|
bin | 110111000001000011… |
… | …1111011100011101111 |
3 | 102021221212212100101122 |
4 | 1232002013323203233 |
5 | 3413431142442111 |
6 | 130135345131155 |
7 | 11351540630231 |
oct | 1560207734357 |
9 | 367855770348 |
10 | 118147234031 |
11 | 46119040682 |
12 | 1aa93329abb |
13 | b1ab3b0c48 |
14 | 5a0b256251 |
15 | 31174c7cdb |
hex | 1b821fb8ef |
118147234031 has 2 divisors, whose sum is σ = 118147234032. Its totient is φ = 118147234030.
The previous prime is 118147233931. The next prime is 118147234207. The reversal of 118147234031 is 130432741811.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 118147234031 - 210 = 118147233007 is a prime.
It is a super-2 number, since 2×1181472340312 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 118147233982 and 118147234000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (118147239031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59073617015 + 59073617016.
It is an arithmetic number, because the mean of its divisors is an integer number (59073617016).
Almost surely, 2118147234031 is an apocalyptic number.
118147234031 is a deficient number, since it is larger than the sum of its proper divisors (1).
118147234031 is an equidigital number, since it uses as much as digits as its factorization.
118147234031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 35.
Adding to 118147234031 its reverse (130432741811), we get a palindrome (248579975842).
The spelling of 118147234031 in words is "one hundred eighteen billion, one hundred forty-seven million, two hundred thirty-four thousand, thirty-one".
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