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11821721300400 = 24352113156950773
BaseRepresentation
bin1010110000000111010101…
…1111111010110110110000
31112212010221002020210210110
42230001311133322312300
53022141341123103100
641050453534501320
72330043163040634
oct254016537726660
945763832223713
1011821721300400
113848622534140
1213ab166664840
13679a25571bab
142cc262650dc4
1515779b8c7250
hexac0757fadb0

11821721300400 has 480 divisors, whose sum is σ = 42719960033280. Its totient is φ = 2768495616000.

The previous prime is 11821721300399. The next prime is 11821721300401. The reversal of 11821721300400 is 400312712811.

It is an interprime number because it is at equal distance from previous prime (11821721300399) and next prime (11821721300401).

It is a Harshad number since it is a multiple of its sum of digits (30).

It is not an unprimeable number, because it can be changed into a prime (11821721300401) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 232809414 + ... + 232860186.

It is an arithmetic number, because the mean of its divisors is an integer number (88999916736).

Almost surely, 211821721300400 is an apocalyptic number.

11821721300400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11821721300400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21359980016640).

11821721300400 is an abundant number, since it is smaller than the sum of its proper divisors (30898238732880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11821721300400 is a wasteful number, since it uses less digits than its factorization.

11821721300400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51405 (or 51394 counting only the distinct ones).

The product of its (nonzero) digits is 2688, while the sum is 30.

It can be divided in two parts, 11821721 and 300400, that added together give a palindrome (12122121).

The spelling of 11821721300400 in words is "eleven trillion, eight hundred twenty-one billion, seven hundred twenty-one million, three hundred thousand, four hundred".