11835354241183 has 4 divisors (see below), whose sum is σ = 12911295535848. Its totient is φ = 10759412946520.

The previous prime is 11835354241159. The next prime is 11835354241211. The reversal of 11835354241183 is 38114245353811.

11835354241183 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11835354241183 is a prime.

It is a super-3 number, since 3×11835354241183³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11835354251183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 537970647316 + ... + 537970647337.

It is an arithmetic number, because the mean of its divisors is an integer number (3227823883962).

Almost surely, 2^{11835354241183} is an apocalyptic number.

11835354241183 is a deficient number, since it is larger than the sum of its proper divisors (1075941294665).

11835354241183 is a wasteful number, since it uses less digits than its factorization.

11835354241183 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1075941294664.

The product of its digits is 1382400, while the sum is 49.

Adding to 11835354241183 its reverse (38114245353811), we get a palindrome (49949599594994).

The spelling of 11835354241183 in words is "eleven trillion, eight hundred thirty-five billion, three hundred fifty-four million, two hundred forty-one thousand, one hundred eighty-three".