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11845055281 is a prime number
BaseRepresentation
bin10110000100000010…
…10011001100110001
31010120111120011011011
423002001103030301
5143224313232111
65235212350521
7566350210603
oct130201231461
933514504134
1011845055281
115029252394
122366a75441
13116a024067
14805207173
15494d66021
hex2c2053331

11845055281 has 2 divisors, whose sum is σ = 11845055282. Its totient is φ = 11845055280.

The previous prime is 11845055231. The next prime is 11845055293. The reversal of 11845055281 is 18255054811.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6547399056 + 5297656225 = 80916^2 + 72785^2 .

It is a cyclic number.

It is not a de Polignac number, because 11845055281 - 29 = 11845054769 is a prime.

It is a super-3 number, since 3×118450552813 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (11845055231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5922527640 + 5922527641.

It is an arithmetic number, because the mean of its divisors is an integer number (5922527641).

Almost surely, 211845055281 is an apocalyptic number.

It is an amenable number.

11845055281 is a deficient number, since it is larger than the sum of its proper divisors (1).

11845055281 is an equidigital number, since it uses as much as digits as its factorization.

11845055281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64000, while the sum is 40.

The spelling of 11845055281 in words is "eleven billion, eight hundred forty-five million, fifty-five thousand, two hundred eighty-one".