118737130019 has 2 divisors, whose sum is σ = 118737130020. Its totient is φ = 118737130018.

The previous prime is 118737130013. The next prime is 118737130021. The reversal of 118737130019 is 910031737811.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-118737130019 is a prime.

It is a super-2 number, since 2×118737130019² (a number of 23 digits) contains 22 as substring.

Together with 118737130021, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (118737130013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59368565009 + 59368565010.

It is an arithmetic number, because the mean of its divisors is an integer number (59368565010).

Almost surely, 2^118737130019 is an apocalyptic number.

118737130019 is a deficient number, since it is larger than the sum of its proper divisors (1).

118737130019 is an equidigital number, since it uses as much as digits as its factorization.

118737130019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31752, while the sum is 41.

The spelling of 118737130019 in words is "one hundred eighteen billion, seven hundred thirty-seven million, one hundred thirty thousand, nineteen".