Search a number
-
+
118966591380 = 223572133124179
BaseRepresentation
bin110111011001011110…
…1100001111110010100
3102101001222122000101010
41232302331201332110
53422120421411010
6130352534532220
711411050225200
oct1566275417624
9371058560333
10118966591380
11464a95a2a0a
121b081807070
13b2ac080890
145a87dbdb00
1531643c5620
hex1bb2f61f94

118966591380 has 864 divisors, whose sum is σ = 447301854720. Its totient is φ = 23398502400.

The previous prime is 118966591319. The next prime is 118966591399. The reversal of 118966591380 is 83195669811.

It is a self number, because there is not a number n which added to its sum of digits gives 118966591380.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 1505906181 + ... + 1505906259.

It is an arithmetic number, because the mean of its divisors is an integer number (517710480).

Almost surely, 2118966591380 is an apocalyptic number.

118966591380 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 118966591380, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (223650927360).

118966591380 is an abundant number, since it is smaller than the sum of its proper divisors (328335263340).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

118966591380 is a wasteful number, since it uses less digits than its factorization.

118966591380 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 221 (or 181 counting only the distinct ones).

The product of its (nonzero) digits is 2799360, while the sum is 57.

The spelling of 118966591380 in words is "one hundred eighteen billion, nine hundred sixty-six million, five hundred ninety-one thousand, three hundred eighty".