11927405951969 has 2 divisors, whose sum is σ = 11927405951970. Its totient is φ = 11927405951968.

The previous prime is 11927405951947. The next prime is 11927405952037. The reversal of 11927405951969 is 96915950472911.

It is an a-pointer prime, because the next prime (11927405952037) can be obtained adding 11927405951969 to its sum of digits (68).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9703773247744 + 2223632704225 = 3115088^2 + 1491185^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11927405951969 is a prime.

It is a super-2 number, since 2×11927405951969² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11927405951899 and 11927405951908.

It is not a weakly prime, because it can be changed into another prime (11927405951939) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5963702975984 + 5963702975985.

It is an arithmetic number, because the mean of its divisors is an integer number (5963702975985).

Almost surely, 2^{11927405951969} is an apocalyptic number.

It is an amenable number.

11927405951969 is a deficient number, since it is larger than the sum of its proper divisors (1).

11927405951969 is an equidigital number, since it uses as much as digits as its factorization.

11927405951969 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 55112400, while the sum is 68.

The spelling of 11927405951969 in words is "eleven trillion, nine hundred twenty-seven billion, four hundred five million, nine hundred fifty-one thousand, nine hundred sixty-nine".