Base | Representation |
---|---|
bin | 110111100110001011… |
… | …0010111001010101101 |
3 | 102102011200002222211221 |
4 | 1233030112113022231 |
5 | 3424003441443432 |
6 | 130503112143341 |
7 | 11424441525046 |
oct | 1571426271255 |
9 | 372150088757 |
10 | 119392531117 |
11 | 466a7a75822 |
12 | 1b180397b51 |
13 | b3493a5022 |
14 | 5ac87b78cd |
15 | 318b9aeb97 |
hex | 1bcc5972ad |
119392531117 has 2 divisors, whose sum is σ = 119392531118. Its totient is φ = 119392531116.
The previous prime is 119392531103. The next prime is 119392531123. The reversal of 119392531117 is 711135293911.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 64590189316 + 54802341801 = 254146^2 + 234099^2 .
It is a cyclic number.
It is not a de Polignac number, because 119392531117 - 215 = 119392498349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (119392531127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59696265558 + 59696265559.
It is an arithmetic number, because the mean of its divisors is an integer number (59696265559).
Almost surely, 2119392531117 is an apocalyptic number.
It is an amenable number.
119392531117 is a deficient number, since it is larger than the sum of its proper divisors (1).
119392531117 is an equidigital number, since it uses as much as digits as its factorization.
119392531117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 51030, while the sum is 43.
The spelling of 119392531117 in words is "one hundred nineteen billion, three hundred ninety-two million, five hundred thirty-one thousand, one hundred seventeen".
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