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11943900569 is a prime number
BaseRepresentation
bin10110001111110100…
…10111010110011001
31010211101120000101202
423013322113112121
5143430114304234
65253103123545
7601660323356
oct130772272631
933741500352
1011943900569
11507a025307
122393ba35b5
1311846520b3
148143b762d
1549d88d77e
hex2c7e97599

11943900569 has 2 divisors, whose sum is σ = 11943900570. Its totient is φ = 11943900568.

The previous prime is 11943900491. The next prime is 11943900571. The reversal of 11943900569 is 96500934911.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8178850969 + 3765049600 = 90437^2 + 61360^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11943900569 is a prime.

It is a super-2 number, since 2×119439005692 (a number of 21 digits) contains 22 as substring.

Together with 11943900571, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11943900169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5971950284 + 5971950285.

It is an arithmetic number, because the mean of its divisors is an integer number (5971950285).

Almost surely, 211943900569 is an apocalyptic number.

It is an amenable number.

11943900569 is a deficient number, since it is larger than the sum of its proper divisors (1).

11943900569 is an equidigital number, since it uses as much as digits as its factorization.

11943900569 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 262440, while the sum is 47.

The spelling of 11943900569 in words is "eleven billion, nine hundred forty-three million, nine hundred thousand, five hundred sixty-nine".