Base | Representation |
---|---|
bin | 110111101000110001… |
… | …0100100011001101101 |
3 | 102102101201222102101221 |
4 | 1233101202210121231 |
5 | 3424143240222013 |
6 | 130515502503341 |
7 | 11426546663122 |
oct | 1572142443155 |
9 | 372351872357 |
10 | 119479617133 |
11 | 46742146838 |
12 | 1b1a5594b51 |
13 | b361446806 |
14 | 5ad61a6749 |
15 | 319446308d |
hex | 1bd18a466d |
119479617133 has 4 divisors (see below), whose sum is σ = 119507780608. Its totient is φ = 119451453660.
The previous prime is 119479617109. The next prime is 119479617151. The reversal of 119479617133 is 331716974911.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-119479617133 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (119479117133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14075373 + ... + 14083858.
It is an arithmetic number, because the mean of its divisors is an integer number (29876945152).
Almost surely, 2119479617133 is an apocalyptic number.
It is an amenable number.
119479617133 is a deficient number, since it is larger than the sum of its proper divisors (28163475).
119479617133 is an equidigital number, since it uses as much as digits as its factorization.
119479617133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28163474.
The product of its digits is 857304, while the sum is 52.
The spelling of 119479617133 in words is "one hundred nineteen billion, four hundred seventy-nine million, six hundred seventeen thousand, one hundred thirty-three".
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