Base | Representation |
---|---|
bin | 110111101011011110… |
… | …0100101011110110101 |
3 | 102102122001122202222121 |
4 | 1233112330211132311 |
5 | 3424340000322011 |
6 | 130532502555541 |
7 | 11432030656615 |
oct | 1572674453665 |
9 | 372561582877 |
10 | 119570323381 |
11 | 4678936a783 |
12 | 1b20ba38bb1 |
13 | b377185052 |
14 | 5b04258a45 |
15 | 319c3cde71 |
hex | 1bd6f257b5 |
119570323381 has 2 divisors, whose sum is σ = 119570323382. Its totient is φ = 119570323380.
The previous prime is 119570323303. The next prime is 119570323421. The reversal of 119570323381 is 183323075911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 71604943281 + 47965380100 = 267591^2 + 219010^2 .
It is a cyclic number.
It is not a de Polignac number, because 119570323381 - 217 = 119570192309 is a prime.
It is a super-2 number, since 2×1195703233812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (119570323181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59785161690 + 59785161691.
It is an arithmetic number, because the mean of its divisors is an integer number (59785161691).
Almost surely, 2119570323381 is an apocalyptic number.
It is an amenable number.
119570323381 is a deficient number, since it is larger than the sum of its proper divisors (1).
119570323381 is an equidigital number, since it uses as much as digits as its factorization.
119570323381 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 43.
The spelling of 119570323381 in words is "one hundred nineteen billion, five hundred seventy million, three hundred twenty-three thousand, three hundred eighty-one".
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