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119570323421 is a prime number
BaseRepresentation
bin110111101011011110…
…0100101011111011101
3102102122001122210001002
41233112330211133131
53424340000322141
6130532503000045
711432030660003
oct1572674453735
9372561583032
10119570323421
114678936a80a
121b20ba39025
13b377185083
145b04258a73
15319c3cde9b
hex1bd6f257dd

119570323421 has 2 divisors, whose sum is σ = 119570323422. Its totient is φ = 119570323420.

The previous prime is 119570323381. The next prime is 119570323427. The reversal of 119570323421 is 124323075911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82031260921 + 37539062500 = 286411^2 + 193750^2 .

It is an emirp because it is prime and its reverse (124323075911) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-119570323421 is a prime.

It is a super-2 number, since 2×1195703234212 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119570323427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59785161710 + 59785161711.

It is an arithmetic number, because the mean of its divisors is an integer number (59785161711).

Almost surely, 2119570323421 is an apocalyptic number.

It is an amenable number.

119570323421 is a deficient number, since it is larger than the sum of its proper divisors (1).

119570323421 is an equidigital number, since it uses as much as digits as its factorization.

119570323421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 45360, while the sum is 38.

The spelling of 119570323421 in words is "one hundred nineteen billion, five hundred seventy million, three hundred twenty-three thousand, four hundred twenty-one".