Base | Representation |
---|---|
bin | 10110010010011001… |
… | …01100100100011011 |
3 | 1010212220011112022211 |
4 | 23021030230210123 |
5 | 144001130431131 |
6 | 5255153455551 |
7 | 602341633636 |
oct | 131114544433 |
9 | 33786145284 |
10 | 11965483291 |
11 | 5090226773 |
12 | 239b2715b7 |
13 | 1188c6aa38 |
14 | 8171d4c1d |
15 | 4a07035b1 |
hex | 2c932c91b |
11965483291 has 2 divisors, whose sum is σ = 11965483292. Its totient is φ = 11965483290.
The previous prime is 11965483289. The next prime is 11965483307. The reversal of 11965483291 is 19238456911.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (19238456911) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11965483291 - 21 = 11965483289 is a prime.
Together with 11965483289, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11965483241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5982741645 + 5982741646.
It is an arithmetic number, because the mean of its divisors is an integer number (5982741646).
Almost surely, 211965483291 is an apocalyptic number.
11965483291 is a deficient number, since it is larger than the sum of its proper divisors (1).
11965483291 is an equidigital number, since it uses as much as digits as its factorization.
11965483291 is an evil number, because the sum of its binary digits is even.
The product of its digits is 466560, while the sum is 49.
The spelling of 11965483291 in words is "eleven billion, nine hundred sixty-five million, four hundred eighty-three thousand, two hundred ninety-one".
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