Base | Representation |
---|---|
bin | 10110010010101111… |
… | …11111111010010101 |
3 | 1010220002202001112112 |
4 | 23021113333322111 |
5 | 144002410233401 |
6 | 5255341200405 |
7 | 602406053603 |
oct | 131127777225 |
9 | 33802661475 |
10 | 11968446101 |
11 | 509196a777 |
12 | 23a0260105 |
13 | 1189767491 |
14 | 817766873 |
15 | 4a0adb3bb |
hex | 2c95ffe95 |
11968446101 has 2 divisors, whose sum is σ = 11968446102. Its totient is φ = 11968446100.
The previous prime is 11968446067. The next prime is 11968446103. The reversal of 11968446101 is 10164486911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6983944900 + 4984501201 = 83570^2 + 70601^2 .
It is an emirp because it is prime and its reverse (10164486911) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11968446101 is a prime.
Together with 11968446103, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11968446103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5984223050 + 5984223051.
It is an arithmetic number, because the mean of its divisors is an integer number (5984223051).
Almost surely, 211968446101 is an apocalyptic number.
It is an amenable number.
11968446101 is a deficient number, since it is larger than the sum of its proper divisors (1).
11968446101 is an equidigital number, since it uses as much as digits as its factorization.
11968446101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 41.
The spelling of 11968446101 in words is "eleven billion, nine hundred sixty-eight million, four hundred forty-six thousand, one hundred one".
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