119742685093 has 2 divisors, whose sum is σ = 119742685094. Its totient is φ = 119742685092.

The previous prime is 119742685079. The next prime is 119742685129. The reversal of 119742685093 is 390586247911.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 91931452804 + 27811232289 = 303202^2 + 166767^2 .

It is an emirp because it is prime and its reverse (390586247911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 119742685093 - 2¹³ = 119742676901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119742685033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59871342546 + 59871342547.

It is an arithmetic number, because the mean of its divisors is an integer number (59871342547).

It is a 2-persistent number, because it is pandigital, and so is 2⋅119742685093 = 239485370186, but 3⋅119742685093 = 359228055279 is not.

Almost surely, 2^119742685093 is an apocalyptic number.

It is an amenable number.

119742685093 is a deficient number, since it is larger than the sum of its proper divisors (1).

119742685093 is an equidigital number, since it uses as much as digits as its factorization.

119742685093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3265920, while the sum is 55.

The spelling of 119742685093 in words is "one hundred nineteen billion, seven hundred forty-two million, six hundred eighty-five thousand, ninety-three".