Base | Representation |
---|---|
bin | 1010111001001110001001… |
… | …0101011101110001101011 |
3 | 1120102002201222202000101100 |
4 | 2232103202111131301223 |
5 | 3032222241010132201 |
6 | 41250405445452443 |
7 | 2344252056634425 |
oct | 256234225356153 |
9 | 46362658660340 |
10 | 11978166099051 |
11 | 38a8a03546969 |
12 | 1415547711123 |
13 | 68b6c80b5479 |
14 | 2d5a63d17815 |
15 | 15b8a61a1886 |
hex | ae4e255dc6b |
11978166099051 has 24 divisors (see below), whose sum is σ = 17522599719456. Its totient is φ = 7883982374400.
The previous prime is 11978166099043. The next prime is 11978166099073. The reversal of 11978166099051 is 15099066187911.
11978166099051 is a `hidden beast` number, since 1 + 1 + 9 + 7 + 8 + 16 + 609 + 9 + 0 + 5 + 1 = 666.
It is not a de Polignac number, because 11978166099051 - 23 = 11978166099043 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11978166099051.
It is not an unprimeable number, because it can be changed into a prime (11978166092051) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 18343855 + ... + 18985608.
It is an arithmetic number, because the mean of its divisors is an integer number (730108321644).
Almost surely, 211978166099051 is an apocalyptic number.
11978166099051 is a deficient number, since it is larger than the sum of its proper divisors (5544433620405).
11978166099051 is a wasteful number, since it uses less digits than its factorization.
11978166099051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37329923 (or 37329920 counting only the distinct ones).
The product of its (nonzero) digits is 7348320, while the sum is 63.
The spelling of 11978166099051 in words is "eleven trillion, nine hundred seventy-eight billion, one hundred sixty-six million, ninety-nine thousand, fifty-one".
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