119794404613 has 4 divisors (see below), whose sum is σ = 129009358828. Its totient is φ = 110579450400.

The previous prime is 119794404581. The next prime is 119794404643. The reversal of 119794404613 is 316404497911.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 31610350849 + 88184053764 = 177793^2 + 296958^2 .

It is a cyclic number.

It is not a de Polignac number, because 119794404613 - 2⁵ = 119794404581 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (119794404643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4607477088 + ... + 4607477113.

It is an arithmetic number, because the mean of its divisors is an integer number (32252339707).

Almost surely, 2^119794404613 is an apocalyptic number.

119794404613 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

119794404613 is a deficient number, since it is larger than the sum of its proper divisors (9214954215).

119794404613 is an equidigital number, since it uses as much as digits as its factorization.

119794404613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9214954214.

The product of its (nonzero) digits is 653184, while the sum is 49.

The spelling of 119794404613 in words is "one hundred nineteen billion, seven hundred ninety-four million, four hundred four thousand, six hundred thirteen".