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11982238823437 is a prime number
BaseRepresentation
bin1010111001011101010100…
…0101101011010000001101
31120102111020211021211221021
42232113111011223100031
53032304111114322222
641252321534234141
72344455022342441
oct256272505532015
946374224254837
1011982238823437
1138aa703491a93
1214162a3655951
1368bbc6aba75c
142d5d2cb9c821
1515ba439deac7
hexae5d516b40d

11982238823437 has 2 divisors, whose sum is σ = 11982238823438. Its totient is φ = 11982238823436.

The previous prime is 11982238823363. The next prime is 11982238823447. The reversal of 11982238823437 is 73432883228911.

It is a happy number.

11982238823437 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11573699256196 + 408539567241 = 3402014^2 + 639171^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11982238823437 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11982238823447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5991119411718 + 5991119411719.

It is an arithmetic number, because the mean of its divisors is an integer number (5991119411719).

Almost surely, 211982238823437 is an apocalyptic number.

It is an amenable number.

11982238823437 is a deficient number, since it is larger than the sum of its proper divisors (1).

11982238823437 is an equidigital number, since it uses as much as digits as its factorization.

11982238823437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 27869184, while the sum is 61.

The spelling of 11982238823437 in words is "eleven trillion, nine hundred eighty-two billion, two hundred thirty-eight million, eight hundred twenty-three thousand, four hundred thirty-seven".