Base | Representation |
---|---|
bin | 10110010100011110… |
… | …11101111011001101 |
3 | 1010221010002210211202 |
4 | 23022033131323031 |
5 | 144020121040312 |
6 | 5301020555245 |
7 | 602643465014 |
oct | 131217357315 |
9 | 33833083752 |
10 | 11982986957 |
11 | 509a0a1507 |
12 | 23a50b2b25 |
13 | 118c788b36 |
14 | 81966da7b |
15 | 4a200e9c2 |
hex | 2ca3ddecd |
11982986957 has 2 divisors, whose sum is σ = 11982986958. Its totient is φ = 11982986956.
The previous prime is 11982986947. The next prime is 11982986987. The reversal of 11982986957 is 75968928911.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6244318441 + 5738668516 = 79021^2 + 75754^2 .
It is a cyclic number.
It is not a de Polignac number, because 11982986957 - 212 = 11982982861 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11982986893 and 11982986902.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11982986927) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5991493478 + 5991493479.
It is an arithmetic number, because the mean of its divisors is an integer number (5991493479).
Almost surely, 211982986957 is an apocalyptic number.
It is an amenable number.
11982986957 is a deficient number, since it is larger than the sum of its proper divisors (1).
11982986957 is an equidigital number, since it uses as much as digits as its factorization.
11982986957 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 19595520, while the sum is 65.
The spelling of 11982986957 in words is "eleven billion, nine hundred eighty-two million, nine hundred eighty-six thousand, nine hundred fifty-seven".
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