Base | Representation |
---|---|
bin | 10110010100101011… |
… | …10011101011001111 |
3 | 1010221020020020121121 |
4 | 23022111303223033 |
5 | 144021032231121 |
6 | 5301120341411 |
7 | 602663556244 |
oct | 131225635317 |
9 | 33836206547 |
10 | 11984648911 |
11 | 50a0027124 |
12 | 23a5774867 |
13 | 118cc1b441 |
14 | 8199835cb |
15 | 4a223c141 |
hex | 2ca573acf |
11984648911 has 4 divisors (see below), whose sum is σ = 12000234400. Its totient is φ = 11969063424.
The previous prime is 11984648891. The next prime is 11984648941.
It is a happy number.
11984648911 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11984648911 - 215 = 11984616143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11984648941) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7791591 + ... + 7793128.
It is an arithmetic number, because the mean of its divisors is an integer number (3000058600).
Almost surely, 211984648911 is an apocalyptic number.
11984648911 is a deficient number, since it is larger than the sum of its proper divisors (15585489).
11984648911 is an equidigital number, since it uses as much as digits as its factorization.
11984648911 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15585488.
The product of its digits is 497664, while the sum is 52.
The spelling of 11984648911 in words is "eleven billion, nine hundred eighty-four million, six hundred forty-eight thousand, nine hundred eleven".
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