1198475187413 has 4 divisors (see below), whose sum is σ = 1369685928480. Its totient is φ = 1027264446348.

The previous prime is 1198475187401. The next prime is 1198475187419. The reversal of 1198475187413 is 3147815748911.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1198475187413 - 2³⁸ = 923597280469 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1198475187419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85605370523 + ... + 85605370536.

It is an arithmetic number, because the mean of its divisors is an integer number (342421482120).

Almost surely, 2^{1198475187413} is an apocalyptic number.

It is an amenable number.

1198475187413 is a deficient number, since it is larger than the sum of its proper divisors (171210741067).

1198475187413 is an equidigital number, since it uses as much as digits as its factorization.

1198475187413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 171210741066.

The product of its digits is 6773760, while the sum is 59.

The spelling of 1198475187413 in words is "one trillion, one hundred ninety-eight billion, four hundred seventy-five million, one hundred eighty-seven thousand, four hundred thirteen".