119884909853 has 2 divisors, whose sum is σ = 119884909854. Its totient is φ = 119884909852.

The previous prime is 119884909819. The next prime is 119884909877. The reversal of 119884909853 is 358909488911.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110568220324 + 9316689529 = 332518^2 + 96523^2 .

It is an emirp because it is prime and its reverse (358909488911) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-119884909853 is a prime.

It is a super-2 number, since 2×119884909853² (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 119884909853.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119884909813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59942454926 + 59942454927.

It is an arithmetic number, because the mean of its divisors is an integer number (59942454927).

Almost surely, 2^119884909853 is an apocalyptic number.

It is an amenable number.

119884909853 is a deficient number, since it is larger than the sum of its proper divisors (1).

119884909853 is an equidigital number, since it uses as much as digits as its factorization.

119884909853 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22394880, while the sum is 65.

The spelling of 119884909853 in words is "one hundred nineteen billion, eight hundred eighty-four million, nine hundred nine thousand, eight hundred fifty-three".