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11992531897 = 96712401791
BaseRepresentation
bin10110010101100111…
…11000001110111001
31010221210001202001001
423022303320032321
5144030042010042
65302001325001
7603120560563
oct131263701671
933853052031
1011992531897
1150a4520795
1223a8336761
13119174b528
1481aa36333
154a2c97bb7
hex2cacf83b9

11992531897 has 4 divisors (see below), whose sum is σ = 12004934656. Its totient is φ = 11980129140.

The previous prime is 11992531883. The next prime is 11992531921. The reversal of 11992531897 is 79813529911.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11992531897 - 223 = 11984143289 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11992531807) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6199929 + ... + 6201862.

It is an arithmetic number, because the mean of its divisors is an integer number (3001233664).

Almost surely, 211992531897 is an apocalyptic number.

It is an amenable number.

11992531897 is a deficient number, since it is larger than the sum of its proper divisors (12402759).

11992531897 is an equidigital number, since it uses as much as digits as its factorization.

11992531897 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12402758.

The product of its digits is 1224720, while the sum is 55.

The spelling of 11992531897 in words is "eleven billion, nine hundred ninety-two million, five hundred thirty-one thousand, eight hundred ninety-seven".

Divisors: 1 967 12401791 11992531897