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11992883048591 is a prime number
BaseRepresentation
bin1010111010000100111110…
…0010001011000010001111
31120110111201122021111211112
42232201033202023002033
53032442411030023331
641301242053042235
72345312551640024
oct256411742130217
946414648244745
1011992883048591
113904175910985
12141837432637b
1368cc020b9533
142d665c6db54b
1515be6820432b
hexae84f88b08f

11992883048591 has 2 divisors, whose sum is σ = 11992883048592. Its totient is φ = 11992883048590.

The previous prime is 11992883048521. The next prime is 11992883048593. The reversal of 11992883048591 is 19584038829911.

It is a strong prime.

It is an emirp because it is prime and its reverse (19584038829911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11992883048591 - 222 = 11992878854287 is a prime.

Together with 11992883048593, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11992883048593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5996441524295 + 5996441524296.

It is an arithmetic number, because the mean of its divisors is an integer number (5996441524296).

Almost surely, 211992883048591 is an apocalyptic number.

11992883048591 is a deficient number, since it is larger than the sum of its proper divisors (1).

11992883048591 is an equidigital number, since it uses as much as digits as its factorization.

11992883048591 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 44789760, while the sum is 68.

The spelling of 11992883048591 in words is "eleven trillion, nine hundred ninety-two billion, eight hundred eighty-three million, forty-eight thousand, five hundred ninety-one".