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11992991700 = 22352173122447
BaseRepresentation
bin10110010101101011…
…01000011111010100
31010221210221002202210
423022311220133110
5144030201213300
65302015233420
7603124514244
oct131265503724
933853832683
1011992991700
1150a4805198
1223a8518870
13119187c8c1
1481ab15b24
154a2d39050
hex2cad687d4

11992991700 has 216 divisors, whose sum is σ = 37979819136. Its totient is φ = 2911718400.

The previous prime is 11992991693. The next prime is 11992991701. The reversal of 11992991700 is 719929911.

It is a self number, because there is not a number n which added to its sum of digits gives 11992991700.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11992991701) by changing a digit.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 4899877 + ... + 4902323.

It is an arithmetic number, because the mean of its divisors is an integer number (175832496).

Almost surely, 211992991700 is an apocalyptic number.

11992991700 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11992991700, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18989909568).

11992991700 is an abundant number, since it is smaller than the sum of its proper divisors (25986827436).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11992991700 is a wasteful number, since it uses less digits than its factorization.

11992991700 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2543 (or 2505 counting only the distinct ones).

The product of its (nonzero) digits is 91854, while the sum is 48.

The spelling of 11992991700 in words is "eleven billion, nine hundred ninety-two million, nine hundred ninety-one thousand, seven hundred".