11994131 has 2 divisors, whose sum is σ = 11994132. Its totient is φ = 11994130.

The previous prime is 11994127. The next prime is 11994133. The reversal of 11994131 is 13149911.

11994131 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11994131 - 2² = 11994127 is a prime.

It is a super-2 number, since 2×11994131² = 287718356890322, which contains 22 as substring.

Together with 11994133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11994094 and 11994103.

It is not a weakly prime, because it can be changed into another prime (11994133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5997065 + 5997066.

It is an arithmetic number, because the mean of its divisors is an integer number (5997066).

Almost surely, 2^11994131 is an apocalyptic number.

11994131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11994131 is an equidigital number, since it uses as much as digits as its factorization.

11994131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 972, while the sum is 29.

The square root of 11994131 is about 3463.2543943522. The cubic root of 11994131 is about 228.9055183803.

The spelling of 11994131 in words is "eleven million, nine hundred ninety-four thousand, one hundred thirty-one".