Base | Representation |
---|---|
bin | 110111111000000010… |
… | …0010001000001100100 |
3 | 102110201102200100010201 |
4 | 1233300010101001210 |
5 | 3431220343022030 |
6 | 131042400000244 |
7 | 11445336122620 |
oct | 1576004210144 |
9 | 373642610121 |
10 | 119991767140 |
11 | 46985251703 |
12 | 1b309000084 |
13 | b413593c5b |
14 | 5b44202180 |
15 | 31c43cb2ca |
hex | 1bf0111064 |
119991767140 has 48 divisors (see below), whose sum is σ = 289571353344. Its totient is φ = 40912732800.
The previous prime is 119991767113. The next prime is 119991767141. The reversal of 119991767140 is 41767199911.
It is a happy number.
It is a Smith number, since the sum of its digits (55) coincides with the sum of the digits of its prime factors.
It is not an unprimeable number, because it can be changed into a prime (119991767141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2342296 + ... + 2392975.
It is an arithmetic number, because the mean of its divisors is an integer number (6032736528).
Almost surely, 2119991767140 is an apocalyptic number.
119991767140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
119991767140 is an abundant number, since it is smaller than the sum of its proper divisors (169579586204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
119991767140 is a wasteful number, since it uses less digits than its factorization.
119991767140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4735468 (or 4735466 counting only the distinct ones).
The product of its (nonzero) digits is 857304, while the sum is 55.
The spelling of 119991767140 in words is "one hundred nineteen billion, nine hundred ninety-one million, seven hundred sixty-seven thousand, one hundred forty".
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