Search a number
-
+
1199964902167 is a prime number
BaseRepresentation
bin10001011101100011011…
…110110101001100010111
311020201022121122221210201
4101131203132311030113
5124130012003332132
62315131204201331
7152460151243003
oct21354336651427
94221277587721
101199964902167
114229a19a4619
12174689999247
1389205249565
14421159cd703
1521331aa62e7
hex117637b5317

1199964902167 has 2 divisors, whose sum is σ = 1199964902168. Its totient is φ = 1199964902166.

The previous prime is 1199964902137. The next prime is 1199964902179. The reversal of 1199964902167 is 7612094699911.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1199964902167 - 27 = 1199964902039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1199964902099 and 1199964902108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1199964902137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 599982451083 + 599982451084.

It is an arithmetic number, because the mean of its divisors is an integer number (599982451084).

Almost surely, 21199964902167 is an apocalyptic number.

1199964902167 is a deficient number, since it is larger than the sum of its proper divisors (1).

1199964902167 is an equidigital number, since it uses as much as digits as its factorization.

1199964902167 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13226976, while the sum is 64.

The spelling of 1199964902167 in words is "one trillion, one hundred ninety-nine billion, nine hundred sixty-four million, nine hundred two thousand, one hundred sixty-seven".