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120000212117 is a prime number
BaseRepresentation
bin110111111000010010…
…0011110110010010101
3102110202000120101110122
41233300210132302111
53431230023241432
6131043301001325
711445500654552
oct1576044366225
9373660511418
10120000212117
1146989a9a525
121b30b9b3245
13b41525ca96
145b4539da29
1531c4ee8612
hex1bf091ec95

120000212117 has 2 divisors, whose sum is σ = 120000212118. Its totient is φ = 120000212116.

The previous prime is 120000212107. The next prime is 120000212147. The reversal of 120000212117 is 711212000021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111698997796 + 8301214321 = 334214^2 + 91111^2 .

It is an emirp because it is prime and its reverse (711212000021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120000212117 - 212 = 120000208021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120000212095 and 120000212104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120000212107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60000106058 + 60000106059.

It is an arithmetic number, because the mean of its divisors is an integer number (60000106059).

Almost surely, 2120000212117 is an apocalyptic number.

It is an amenable number.

120000212117 is a deficient number, since it is larger than the sum of its proper divisors (1).

120000212117 is an equidigital number, since it uses as much as digits as its factorization.

120000212117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 17.

Adding to 120000212117 its reverse (711212000021), we get a palindrome (831212212138).

The spelling of 120000212117 in words is "one hundred twenty billion, two hundred twelve thousand, one hundred seventeen".