Base | Representation |
---|---|
bin | 1010111010011111110110… |
… | …1101011011011000100111 |
3 | 1120111012100121121220010111 |
4 | 2232213331231123120213 |
5 | 3033102201122431043 |
6 | 41304434145433451 |
7 | 2345656445505463 |
oct | 256477555333047 |
9 | 46435317556114 |
10 | 12000100202023 |
11 | 39072397a409a |
12 | 141984933b887 |
13 | 6907b23a431b |
14 | 2d6b450234a3 |
15 | 15c23bb1509d |
hex | ae9fdb5b627 |
12000100202023 has 2 divisors, whose sum is σ = 12000100202024. Its totient is φ = 12000100202022.
The previous prime is 12000100201993. The next prime is 12000100202033. The reversal of 12000100202023 is 32020200100021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12000100202023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12000100201994 and 12000100202012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12000100202033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000050101011 + 6000050101012.
It is an arithmetic number, because the mean of its divisors is an integer number (6000050101012).
Almost surely, 212000100202023 is an apocalyptic number.
12000100202023 is a deficient number, since it is larger than the sum of its proper divisors (1).
12000100202023 is an equidigital number, since it uses as much as digits as its factorization.
12000100202023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 12000100202023 its reverse (32020200100021), we get a palindrome (44020300302044).
The spelling of 12000100202023 in words is "twelve trillion, one hundred million, two hundred two thousand, twenty-three".
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