Base | Representation |
---|---|
bin | 10001011101100110010… |
… | …010111000100111010111 |
3 | 11020201102220110221221111 |
4 | 101131212102320213113 |
5 | 124130111044231403 |
6 | 2315140011555451 |
7 | 152461263366103 |
oct | 21354622704727 |
9 | 4221386427844 |
10 | 1200012102103 |
11 | 422a16602631 |
12 | 1746a175bb87 |
13 | 89211c64309 |
14 | 4211bd98903 |
15 | 21335ccb56d |
hex | 117664b89d7 |
1200012102103 has 2 divisors, whose sum is σ = 1200012102104. Its totient is φ = 1200012102102.
The previous prime is 1200012102011. The next prime is 1200012102119. The reversal of 1200012102103 is 3012012100021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1200012102103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1200012102173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600006051051 + 600006051052.
It is an arithmetic number, because the mean of its divisors is an integer number (600006051052).
Almost surely, 21200012102103 is an apocalyptic number.
1200012102103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200012102103 is an equidigital number, since it uses as much as digits as its factorization.
1200012102103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 1200012102103 its reverse (3012012100021), we get a palindrome (4212024202124).
The spelling of 1200012102103 in words is "one trillion, two hundred billion, twelve million, one hundred two thousand, one hundred three".
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