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120001300012112 = 247500081250757
BaseRepresentation
bin11011010010001111111010…
…110111000001110001010000
3120201220000022220222111022012
4123102033322313001301100
5111212100130300341422
61103115500340402052
734163544040125011
oct3322177267016120
9521800286874265
10120001300012112
11352662a147a592
12115610806a6328
1351c60c686a2cc
14218c145995008
15dd17988494e2
hex6d23fadc1c50

120001300012112 has 10 divisors (see below), whose sum is σ = 232502518773498. Its totient is φ = 60000650006048.

The previous prime is 120001300012067. The next prime is 120001300012183. The reversal of 120001300012112 is 211210003100021.

It can be written as a sum of positive squares in only one way, i.e., 107755527647296 + 12245772364816 = 10380536^2 + 3499396^2 .

It is a super-2 number, since 2×1200013000121122 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3750040625363 + ... + 3750040625394.

Almost surely, 2120001300012112 is an apocalyptic number.

It is an amenable number.

120001300012112 is a deficient number, since it is larger than the sum of its proper divisors (112501218761386).

120001300012112 is an equidigital number, since it uses as much as digits as its factorization.

120001300012112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7500081250765 (or 7500081250759 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 120001300012112 its reverse (211210003100021), we get a palindrome (331211303112133).

The spelling of 120001300012112 in words is "one hundred twenty trillion, one billion, three hundred million, twelve thousand, one hundred twelve".

Divisors: 1 2 4 8 16 7500081250757 15000162501514 30000325003028 60000650006056 120001300012112