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120001343400143 is a prime number
BaseRepresentation
bin11011010010001111111101…
…011100100010100011001111
3120201220000102221121211111022
4123102033331130202203033
5111212100222402301033
61103115504530344355
734163545104663512
oct3322177534424317
9521800387554438
10120001343400143
1135266313a14667
121156109312b0bb
1351c610284bcba
14218c14b64ad79
15dd179c56a098
hex6d23fd7228cf

120001343400143 has 2 divisors, whose sum is σ = 120001343400144. Its totient is φ = 120001343400142.

The previous prime is 120001343400139. The next prime is 120001343400149. The reversal of 120001343400143 is 341004343100021.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (341004343100021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120001343400143 - 22 = 120001343400139 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120001343400149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60000671700071 + 60000671700072.

It is an arithmetic number, because the mean of its divisors is an integer number (60000671700072).

Almost surely, 2120001343400143 is an apocalyptic number.

120001343400143 is a deficient number, since it is larger than the sum of its proper divisors (1).

120001343400143 is an equidigital number, since it uses as much as digits as its factorization.

120001343400143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 120001343400143 its reverse (341004343100021), we get a palindrome (461005686500164).

The spelling of 120001343400143 in words is "one hundred twenty trillion, one billion, three hundred forty-three million, four hundred thousand, one hundred forty-three".