120002000112121 has 4 divisors (see below), whose sum is σ = 120003284927232. Its totient is φ = 120000715297012.

The previous prime is 120002000112119. The next prime is 120002000112131. The reversal of 120002000112121 is 121211000200021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120002000112121 - 2¹ = 120002000112119 is a prime.

It is a super-3 number, since 3×120002000112121³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120002000112131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 642267445 + ... + 642454258.

It is an arithmetic number, because the mean of its divisors is an integer number (30000821231808).

Almost surely, 2^{120002000112121} is an apocalyptic number.

It is an amenable number.

120002000112121 is a deficient number, since it is larger than the sum of its proper divisors (1284815111).

120002000112121 is an equidigital number, since it uses as much as digits as its factorization.

120002000112121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1284815110.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 120002000112121 its reverse (121211000200021), we get a palindrome (241213000312142).

The spelling of 120002000112121 in words is "one hundred twenty trillion, two billion, one hundred twelve thousand, one hundred twenty-one".